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Fix social URL host matching (#1174)

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Co-authored-by: MaheshtheDev <38828053+MaheshtheDev@users.noreply.github.com>
This commit is contained in:
Anirudh Sharma 2026-06-28 12:36:26 +05:30 • committed by GitHub
parent f1e2d3b41b
commit 5d975eb0c9
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1 changed files with 35 additions and 8 deletions
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43
apps/web/lib/url-helpers.ts
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@ -77,7 +77,7 @@ export const isValidUrl = (url: string): boolean => {
*/
export const normalizeUrl = (url: string): string => {
if (!url.trim()) return ""
if (url.startsWith("http://") || url.startsWith("https://")) {
if (/^https?:\/\//i.test(url)) {
return url
}
return `https://${url}`
@ -120,13 +120,40 @@ export const extractUrls = (
return { urls, duplicates }
}
const parseWebUrl = (url: string): URL | null => {
const trimmed = url.trim()
if (!trimmed) return null
try {
const parsed = new URL(trimmed)
return parsed.protocol === "http:" || parsed.protocol === "https:"
? parsed
: null
} catch {
try {
return new URL(`https://${trimmed}`)
} catch {
return null
}
}
}
const hostnameMatches = (hostname: string, domain: string): boolean => {
const normalizedHostname = hostname.toLowerCase()
return (
normalizedHostname === domain || normalizedHostname.endsWith(`.${domain}`)
)
}
/**
* Checks if a URL is a Twitter/X URL.
*/
export const isTwitterUrl = (url: string): boolean => {
const normalizedUrl = url.toLowerCase()
const parsed = parseWebUrl(url)
if (!parsed) return false
return (
normalizedUrl.includes("twitter.com") || normalizedUrl.includes("x.com")
hostnameMatches(parsed.hostname, "twitter.com") ||
hostnameMatches(parsed.hostname, "x.com")
)
}
@ -134,11 +161,11 @@ export const isTwitterUrl = (url: string): boolean => {
* Checks if a URL is a LinkedIn profile URL (not a company page).
*/
export const isLinkedInProfileUrl = (url: string): boolean => {
const normalizedUrl = url.toLowerCase()
return (
normalizedUrl.includes("linkedin.com/in/") &&
!normalizedUrl.includes("linkedin.com/company/")
)
const parsed = parseWebUrl(url)
if (!parsed || !hostnameMatches(parsed.hostname, "linkedin.com")) return false
const [section, handle] = parsed.pathname.split("/").filter(Boolean)
return section?.toLowerCase() === "in" && Boolean(handle)
}
/**