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refactor(langfuse_otel): flatten output items with itertools.chain to satisfy LIT014 budget

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Co-Authored-By: Devin AI <158243242+devin-ai-integration[bot]@users.noreply.github.com>
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yucheng 2026-09-25 22:28:52 +00:00
parent 76e6b79725
commit 73cc218b2d
1 changed files with 2 additions and 1 deletions
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litellm/integrations/langfuse/langfuse_otel.py
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@ -3,6 +3,7 @@ import json
import os
from collections.abc import Iterable, Mapping, Sequence
from datetime import datetime
from itertools import chain
from typing import TYPE_CHECKING, Any, Final, Optional, Protocol, runtime_checkable
from litellm._logging import verbose_logger
@ -498,7 +499,7 @@ def _extract_output_items(response_obj: _Gettable) -> str | None:
output: Final = response_obj.get("output", [])
if not isinstance(output, list) or not output:
return None
rendered: Final = tuple(entry for item in output for entry in _output_items(item))
rendered: Final = tuple(chain.from_iterable(map(_output_items, output)))
return safe_dumps(list(rendered)) if rendered else None