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fix(mutation report): correctly parse function names with leading underscores

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mutmut's mutant-name prefix is x_ (single underscore), so a function
named _foo produces mutants x__foo__mutmut_N. The previous regex
\.x__(.+)__mutmut_ ate the function's leading underscore as part of
the prefix. Changed to \.x_(.+)__mutmut_ so leading underscores are
preserved in the captured function name; verified for normal, leading-
underscore, and dunder-method names.
This commit is contained in:
Ryan Crabbe 2026-05-09 18:45:18 -07:00 • committed by Cursor Agent
parent c2098389b2
commit 5289bd9ebe
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1 changed files with 9 additions and 2 deletions
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11
scripts/mutation_report.py
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@ -55,8 +55,15 @@ def get_mutmut_show(mutant_name: str) -> str:
def parse_mutant_name(name: str) -> tuple[str, str, str]:
"""Parse `<dotted.module>.x__<function>__mutmut_<N>` -> (module, function, N)."""
m = re.match(r"^(.+)\.x__(.+)__mutmut_(\d+)$", name)
"""Parse `<dotted.module>.x_<function>__mutmut_<N>` -> (module, function, N).
mutmut prefixes mutated functions with `x_` (single underscore). For a
function named `foo`, mutants are `x_foo__mutmut_N`. For a function named
`_foo` (leading underscore), the mutant becomes `x__foo__mutmut_N` — so
the regex matches a single underscore after `x` and captures everything
(including any leading underscores) up to `__mutmut_<N>`.
"""
m = re.match(r"^(.+)\.x_(.+)__mutmut_(\d+)$", name)
if not m:
return name, name, "?"
return m.group(1), m.group(2), m.group(3)